MySQL死鎖套路之唯一索引下批量插入順序不一致
死鎖的本質(zhì)是資源競爭,批量插入如果順序不一致很容易導(dǎo)致死鎖,我們來分析一下這個情況。為了方便演示,把批量插入改寫為了多條 insert。
先來做幾個小實驗,簡化的表結(jié)構(gòu)如下
CREATE TABLE `t1` ( `id` int(11) NOT NULL AUTO_INCREMENT, `a` varchar(5), `b` varchar(5), PRIMARY KEY (`id`), UNIQUE KEY `uk_name` (`a`,`b`) );
實驗1:
在記錄不存在的情況下,兩個同樣順序的批量 insert 同時執(zhí)行,第二個會進行鎖等待狀態(tài)
t1 | t2 | |
---|---|---|
begin; | begin; | |
insert ignore into t1(a, b)values("1", "1"); | 成功 | |
insert ignore into t1(a, b)values("1", "1"); | 鎖等待狀態(tài) |
可以看到目前鎖的狀態(tài)
mysql> select * from information_schema.innodb_locks; +-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+ | lock_id | lock_trx_id | lock_mode | lock_type | lock_table | lock_index | lock_space | lock_page | lock_rec | lock_data | +-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+ | 31AE:54:4:2 | 31AE | S | RECORD | `d1`.`t1` | `uk_name` | 54 | 4 | 2 | '1', '1' | | 31AD:54:4:2 | 31AD | X | RECORD | `d1`.`t1` | `uk_name` | 54 | 4 | 2 | '1', '1' | +-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+
在我們執(zhí)行事務(wù)t1的 insert 時,沒有在任何鎖的斷點處出現(xiàn),這跟 MySQL 插入的原理有關(guān)系
insert 加的是隱式鎖。什么是隱式鎖?隱式鎖的意思就是沒有鎖
在 t1 插入記錄時,是不加鎖的。這個時候事務(wù) t1 還未提交的情況下,事務(wù) t2 嘗試插入的時候,發(fā)現(xiàn)有這條記錄,t2 嘗試獲取 S 鎖,會判定記錄上的事務(wù) id 是否活躍,如果活躍的話,說明事務(wù)未結(jié)束,會幫 t1 把它的隱式鎖提升為顯式鎖( X 鎖)
源碼如下
t2 獲取S鎖的結(jié)果:DB_LOCK_WAIT
實驗2:
批量插入順序不一致的導(dǎo)致的死鎖
t1 | t2 | |
---|---|---|
begin | ||
insert into t1(a, b)values("1", "1"); | 成功 | |
insert into t1(a, b)values("2", "2"); | 成功 | |
insert into t1(a, b)values("2", "2"); | t1 嘗試獲取 S 鎖,把 t2 的隱式鎖提升為顯式 X 鎖,進入 DB_LOCK_WAIT | |
insert into t1(a, b)values("1", "1"); | t2 嘗試獲取 S 鎖,把 t1 的隱式鎖提升為顯式 X 鎖,產(chǎn)生死鎖 |
------------------------ LATEST DETECTED DEADLOCK ------------------------ 181101 9:48:36 *** (1) TRANSACTION: TRANSACTION 3309, ACTIVE 215 sec inserting mysql tables in use 1, locked 1 LOCK WAIT 3 lock struct(s), heap size 376, 2 row lock(s), undo log entries 2 MySQL thread id 2, OS thread handle 0x70000a845000, query id 58 localhost root update insert into t1(a, b)values("2", "2") *** (1) WAITING FOR THIS LOCK TO BE GRANTED: RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 3309 lock mode S waiting Record lock, heap no 3 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 1; hex 32; asc 2;; 1: len 1; hex 32; asc 2;; 2: len 4; hex 80000002; asc ;; *** (2) TRANSACTION: TRANSACTION 330A, ACTIVE 163 sec inserting mysql tables in use 1, locked 1 3 lock struct(s), heap size 376, 2 row lock(s), undo log entries 2 MySQL thread id 3, OS thread handle 0x70000a888000, query id 59 localhost root update insert into t1(a, b)values("1", "1") *** (2) HOLDS THE LOCK(S): RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 330A lock_mode X locks rec but not gap Record lock, heap no 3 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 1; hex 32; asc 2;; 1: len 1; hex 32; asc 2;; 2: len 4; hex 80000002; asc ;; *** (2) WAITING FOR THIS LOCK TO BE GRANTED: RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 330A lock mode S waiting Record lock, heap no 2 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 1; hex 31; asc 1;; 1: len 1; hex 31; asc 1;; 2: len 4; hex 80000001; asc ;; *** WE ROLL BACK TRANSACTION (2)
怎么樣解決這樣的問題呢?
一個可行的辦法是在應(yīng)用層排序以后再插入
總結(jié)
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