MySQL按小時查詢數(shù)據(jù),沒有的補0
需求背景
一個統(tǒng)計接口,前端需要返回兩個數(shù)組,一個是0-23的小時計數(shù),一個是各小時對應(yīng)的統(tǒng)計數(shù)。
思路 直接使用group by查詢要統(tǒng)計的表,當(dāng)某個小時統(tǒng)計數(shù)為0時,會沒有該小時分組。思考了一下,需要建立輔助表,只有一列小時,再插入0-23共24個小時
CREATE TABLE hours_list ( hour int NOT NULL PRIMARY KEY )
先查小時表,再做連接需要查的表,即可將沒有統(tǒng)計數(shù)的小時填充上0。這里由于需要查多個表中,create_time在每個小時區(qū)間內(nèi)、且SOURCE_ID等于查詢條件的統(tǒng)計之和,所以UNION ALL了多張表
SELECT t.HOUR, sum(t.HOUR_COUNT) hourCount FROM (SELECT hs. HOUR AS HOUR, COUNT(cs.RECORD_ID) AS HOUR_COUNT FROM cbc_hours_list hs LEFT JOIN cbc_source_0002 cs ON HOUR (cs.create_time) = hs. HOUR AND cs.create_time > #{startTime} AND cs.create_time <= #{endTime} <#if sourceId?exists && sourceId !=''> AND SOURCE_ID = #{sourceId} </#if> GROUP BY hs. HOUR UNION ALL SELECT hs.HOUR AS HOUR, COUNT(cs.RECORD_ID) AS HOUR_COUNT FROM cbc_hours_list hs LEFT JOIN cbc_source_hs cs ON HOUR (cs.create_time) = hs. HOUR AND cs.create_time > #{startTime} AND cs.create_time <= #{endTime} <#if sourceId?exists && sourceId !=''> AND SOURCE_ID = #{sourceId} </#if> GROUP BY hs. HOUR UNION ALL SELECT hs.HOUR AS HOUR, COUNT(cs.RECORD_ID) AS HOUR_COUNT FROM cbc_hours_list hs LEFT JOIN cbc_source_kfyj cs ON HOUR (cs.create_time) = hs. HOUR AND cs.create_time > #{startTime} AND cs.create_time <= #{endTime} <#if sourceId?exists && sourceId !=''> AND SOURCE_ID = #{sourceId} </#if> GROUP BY hs. HOUR UNION ALL SELECT hs.HOUR AS HOUR, COUNT(cs.RECORD_ID) AS HOUR_COUNT FROM cbc_hours_list hs LEFT JOIN cbc_source_his_0002 cs ON HOUR (cs.create_time) = hs. HOUR AND cs.create_time > #{startTime} AND cs.create_time <= #{endTime} <#if sourceId?exists && sourceId !=''> AND SOURCE_ID = #{sourceId} </#if> GROUP BY hs. HOUR UNION ALL SELECT hs.HOUR AS HOUR, COUNT(cs.RECORD_ID) AS HOUR_COUNT FROM cbc_hours_list hs LEFT JOIN cbc_source_his_hs cs ON HOUR (cs.create_time) = hs. HOUR AND cs.create_time > #{startTime} AND cs.create_time <= #{endTime} <#if sourceId?exists && sourceId !=''> AND SOURCE_ID = #{sourceId} </#if> GROUP BY hs. HOUR UNION ALL SELECT hs.HOUR AS HOUR, COUNT(cs.RECORD_ID) AS HOUR_COUNT FROM cbc_hours_list hs LEFT JOIN cbc_source_his_kfyj cs ON HOUR (cs.create_time) = hs. HOUR AND cs.create_time > #{startTime} AND cs.create_time <= #{endTime} <#if sourceId?exists && sourceId !=''> AND SOURCE_ID = #{sourceId} </#if> GROUP BY hs. HOUR) t GROUP BY t.hour
效果
統(tǒng)計數(shù)為0的小時也可以查出來了。
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