[LeetCode] 181.Employees Earning More Than Their Managers 員工掙得比經(jīng)理多

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+
| Employee |
+----------+
| Joe      |
+----------+

這道題給我們了一個Employee表，里面有員工的薪水信息和其經(jīng)理的信息，經(jīng)理也屬于員工，其經(jīng)理Id為空，讓我們找出薪水比其經(jīng)理高的員工，那么就是一個很簡單的比較問題了，我們可以生成兩個實例對象進(jìn)行內(nèi)交通過ManagerId和Id，然后限制條件是一個Salary大于另一個即可：

解法一：

SELECT e1.Name FROM Employee e1
JOIN Employee e2 ON e1.ManagerId = e2.Id
WHERE e1.Salary > e2.Salary;

我們也可以不用Join，直接把條件都寫到where里也行：

解法二：

SELECT e1.Name FROM Employee e1, Employee e2
WHERE e1.ManagerId = e2.Id AND e1.Salary > e2.Salary;

參考資料：

https://leetcode.com/discuss/88189/two-straightforward-way-using-where-and-join

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