1.計(jì)算每個(gè)人的總成績(jī)并排名 select name,sum(score) as allscore from stuscore group by name order by allscore 2.計(jì)算每個(gè)人的總成績(jī)并排名 select distinct t1.name,t1.stuid,t2.allscore from stuscore t1,( select stuid,sum(score) as allscore from stuscore group by stuid)t2where t1.stuid=t2.stuidorder by t2.allscore desc 3. 計(jì)算每個(gè)人單科的最高成績(jī) select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,(select stuid,max(score) as maxscore from stuscore group by stuid) t2where t1.stuid=t2.stuid and t1.score=t2.maxscore 4.計(jì)算每個(gè)人的平均成績(jī)

select distinct t1.stuid,t1.name,t2.avgscore from stuscore t1,(select stuid,avg(score) as avgscore from stuscore group by stuid) t2where t1.stuid=t2.stuid 5.列出各門課程成績(jī)最好的學(xué)生

select t1.stuid,t1.name,t1.subject,t2.maxscore from stuscore t1,(select subject,max(score) as maxscore from stuscore group by subject) t2where t1.subject=t2.subject and t1.score=t2.maxscore
6.列出各門課程成績(jī)最好的兩位學(xué)生

select distinct t1.* from stuscore t1 where t1.id in (select top 2 stuscore.id from stuscore where subject = t1.subject order by score desc) order by t1.subject 7.學(xué)號(hào) 姓名 語文 數(shù)學(xué) 英語 總分 平均分 select stuid as 學(xué)號(hào),name as 姓名,sum(case when subject='語文' then score else 0 end) as 語文,sum(case when subject='數(shù)學(xué)' then score else 0 end) as 數(shù)學(xué),sum(case when subject='英語' then score else 0 end) as 英語,sum(score) as 總分,(sum(score)/count(*)) as 平均分from stuscoregroup by stuid,name order by 總分desc 8.列出各門課程的平均成績(jī) select subject,avg(score) as avgscore from stuscoregroup by subject 9.列出數(shù)學(xué)成績(jī)的排名 declare @tmp table(pm int,name varchar(50),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='數(shù)學(xué)' order by score descdeclare @id intset @id=0;update @tmp set @id=@id+1,pm=@idselect * from @tmp select DENSE_RANK () OVER(order by score desc) as row,name,subject,score,stuid from stuscore where subject='數(shù)學(xué)'order by score desc 10. 列出數(shù)學(xué)成績(jī)?cè)?-3名的學(xué)生 select t3.* from(select top 2 t2.* from (select top 3 name,subject,score,stuid from stuscore where subject='數(shù)學(xué)'order by score desc) t2 order by t2.score) t3 order by t3.score desc 11. 求出李四的數(shù)學(xué)成績(jī)的排名 declare @tmp table(pm int,name varchar(50),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='數(shù)學(xué)' order by score descdeclare @id intset @id=0;update @tmp set @id=@id+1,pm=@idselect * from @tmp where name='李四' 12. 課程 不及格（-59） 良（-80） 優(yōu)（-100）

select subject, (select count(*) from stuscore where score<60 and subject=t1.subject) as 不及格,(select count(*) from stuscore where score between 60 and 80 and subject=t1.subject) as 良,(select count(*) from stuscore where score >80 and subject=t1.subject) as 優(yōu)from stuscore t1 group by subject 13. 數(shù)學(xué):張三(50分),李四(90分),王五(90分),趙六(76分)

declare @s varchar(1000)set @s=''select @s =@s+','+name+'('+convert(varchar(10),score)+'分)' from stuscore where subject='數(shù)學(xué)' set @s=stuff(@s,1,1,'')print '數(shù)學(xué):'+@s

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